macd histogram scan |
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pinto
Newbie Joined: 29 Aug 2008 Posts: 2 |
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Topic: macd histogram scan Posted: 29 Aug 2008 at 10:43am |
Hi, I would like to run a scan that tells me when a weekly macd histogram first ticks upward after several weeks decent. Can anyone help please? tia Pinto |
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maximo
BullCharts Guru Joined: 02 Sep 2006 Location: Australia Posts: 232 |
Post Options Quote Reply Posted: 31 Aug 2008 at 8:40pm |
Hi Pinto,
What a great idea for a scan! This finds the start of all new uptrends and
often well before the MACD crosses over.
I created a simplified MACD indicator which is 99.5% the same and it checks for
this signal: 3 descents before 1 ascent of the histogram and this must be
below the zero line. Add the following new indicator and create a new scan,
select 'is an indicator signal' and weekly or daily whichever you choose.
{ Trend MAC } [Description:="Simplified MACD"] a1 := input("Short MA",12,1);a2 := input("Long MA",26,1);a3 := input("Signal period",9,1);[color =blue]mac:=( C*ma(C,a1,E)-C*ma(C,a2,E))*.20;mac; [color =red]ma (mac,a3,E)[Name =Histogram; linestyle=Histogram; color=black]histogram:=mac- ma(mac,a3,E);histogram; [Name =" "; linestyle=Marker; marker=Long]descent3:= if(histogram < 0 and histogram > hist(histogram,1) and hist(histogram,1)<=hist(histogram,2) and hist(histogram,2)<=hist(histogram,3) and hist(histogram,3)<=hist(histogram,4),1,undefined);descent3; Edited by maximo - 01 Sep 2008 at 3:54pm |
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pinto
Newbie Joined: 29 Aug 2008 Posts: 2 |
Post Options Quote Reply Posted: 02 Sep 2008 at 8:02am |
Hi Maximo,
thanks for that. I have built the indicator and scan and it certainly shows up interesting things, however, it misses some of the things I want. It is probably my lack of knowledge I suspect -------- here is an example of what I want it to find. If you look at a weekly chart of ipl ---- you will see that the weekly macd jumped on the week ending 22/8/08 ------------- the scan misses that signal. Is it because there are not enough (consistent) weeks in decline before that? It does, however, give a signal on the week ending 1/8/08. The scan I want would not be the only criteria for a long entry as many times the weekly macd will begin an upward movement whilst the price is still in decline. I have noticed that when this happens a lot of the time the price will begin an upward movement when the macd gets somewhat closer to the line. This is often the start of a solid up trend. Along with macd I look at momentum indicators on a shorter time frame as well as financial strength ---- it doesn't often happen but when the 3 are in alignment it really can be party time. Pinto |
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maximo
BullCharts Guru Joined: 02 Sep 2006 Location: Australia Posts: 232 |
Post Options Quote Reply Posted: 02 Sep 2008 at 5:45pm |
Yes I could see exactly from your example, thanks that helps. I replaced the code with original MACD formula and made the histogram detection a fraction flexible. ie. 99.9% is close enough to allow a signal. IPL was missed from the weekly scan because the ascent bar of the histogram was within 1% higher of the previous bar. It's now close enough to pass the scan. I really like this entry signal and speaking of financial strength (TA wise) it would go well with those closing above the 41 MA weekly & 200 MA daily. Can see by looking at a few charts that at least 2 out of 3 signals result in a price swing.{ MACD+ } [Description:="MACD+ Momentum Swing Signal"] a1 := input("Short MA",12,1);a2 := input("Long MA",26,1);a3 := input("Signal period",9,1);r1 := 2/(a1+1); r2 := 2/(a2+1); ma12 := C*r1 + previous(C)*(1-r1);ma26 := C*r2 + previous(C)*(1-r2);res := wait(ma12 - ma26,25);signal := ma(res,a3,E);[Name =MACD; color=dodger blue]res; [name =Signal; linestyle=solid; color=red]signal; [color =navy]0; [Name =Histogram; linestyle=Histogram; color=black]histogram:=res - signal; histogram; [Name =" "; linestyle=Marker; marker=Long]descent3:= if(histogram < 0 and histogram*0.999 > hist(histogram,1) and hist(histogram*0.999,1) < hist(histogram,2) and hist(histogram*0.999,2) < hist(histogram,3) and hist(histogram,3) < hist(histogram,4),1,undefined);descent3; Edited by maximo - 03 Sep 2008 at 3:07am |
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